D02TYF Example Program Results Tolerance = 0.1E-04 A = 1.00 Used a mesh of 11 points Maximum error = 0.31E-05 in interval 1 for component 1 Mesh points: 1(1) 0.0000E+00 2(3) 0.1000E+00 3(2) 0.2000E+00 4(3) 0.3000E+00 5(2) 0.4000E+00 6(3) 0.5000E+00 7(2) 0.6000E+00 8(3) 0.7000E+00 9(2) 0.8000E+00 10(3) 0.9000E+00 11(1) 0.1000E+01 Computed solution x solution derivative 0.00 1.00000 -1.84496 0.10 0.84944 -1.32330 0.20 0.72721 -1.13911 0.30 0.61927 -1.02776 0.40 0.52040 -0.95468 0.50 0.42754 -0.90583 0.60 0.33867 -0.87372 0.70 0.25239 -0.85369 0.80 0.16764 -0.84248 0.90 0.08368 -0.83756 1.00 0.00000 -0.83655